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'load lines for dissimilar output tubes?'
Author:tapehead ted (registered user: 6 posts )
Date: Sun, Mar 19th, 2017 @ 19:31 ( . )

Malcolm's suggestion was very easily done- I thought at first suspiciously so. I just tried it on the only charts I had with -10 lines, just drew a load line through -10 on each. They were equidistant in current from the 2k class b line, and right through the knee on both graphs! The results tallied exactly with my equations, but the graphic approach made it so much easier to see. I'm no longer concerned about bias shift. it's the ratio of currents at vg1 eequals zero that counts, and that is constant on the linear part of the characteristic. You could do this with only the vg1 equals zero chart.

This design just got a whole lot simpler! Thank you!

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